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fix: ganti '//n' jadi '/n'

This commit is contained in:
a2nr 2026-05-05 14:09:40 +07:00
parent 885980f276
commit 6088254959
19 changed files with 161 additions and 161 deletions
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22
content/arrays.md
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@ -98,7 +98,7 @@ for (int i = 0; i < 5; i++) {
int myNumbers[5] = {10, 20, 30, 40, 50};
for (int i = 0; i < 5; i++) {
printf("%d\\n", myNumbers[i]);
printf("%d\n", myNumbers[i]);
}
```
@ -124,15 +124,15 @@ int main() {
int total = 0;
int arraySize = sizeof(scores) / sizeof(scores[0]);
printf("Nilai ujian siswa:\\n");
printf("Nilai ujian siswa:\n");
for (int i = 0; i < arraySize; i++) {
printf("Siswa %d: %d\\n", i+1, scores[i]);
printf("Siswa %d: %d\n", i+1, scores[i]);
total += scores[i];
}
float average = (float)total / arraySize;
printf("\\nTotal nilai: %d\\n", total);
printf("Rata-rata nilai: %.2f\\n", average);
printf("\nTotal nilai: %d\n", total);
printf("Rata-rata nilai: %.2f\n", average);
return 0;
}
@ -229,9 +229,9 @@ int main() {
// TODO: Hitung rata-rata
float average = 0.0;
printf("Total nilai: %d\\n", total);
printf("Jumlah siswa: %d\\n", count);
printf("Rata-rata nilai: %.2f\\n", average);
printf("Total nilai: %d\n", total);
printf("Jumlah siswa: %d\n", count);
printf("Rata-rata nilai: %.2f\n", average);
return 0;
}
@ -254,9 +254,9 @@ int main() {
// Hitung rata-rata
float average = (float)total / count;
printf("Total nilai: %d\\n", total);
printf("Jumlah siswa: %d\\n", count);
printf("Rata-rata nilai: %.2f\\n", average);
printf("Total nilai: %d\n", total);
printf("Jumlah siswa: %d\n", count);
printf("Rata-rata nilai: %.2f\n", average);
return 0;
}

12
content/arrays_and_pointers.md
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@ -30,12 +30,12 @@ int i;
// Print the addresses
for (i = 0; i < 5; i++) {
printf("&vowels[%d]: %p, pvowels + %d: %p, vowels + %d: %p\\n", i, &vowels[i], i, pvowels + i, i, vowels + i);
printf("&vowels[%d]: %p, pvowels + %d: %p, vowels + %d: %p\n", i, &vowels[i], i, pvowels + i, i, vowels + i);
}
// Print the values
for (i = 0; i < 5; i++) {
printf("vowels[%d]: %c, *(pvowels + %d): %c, *(vowels + %d): %c\\n", i, vowels[i], i, *(pvowels + i), i, *(vowels + i));
printf("vowels[%d]: %c, *(pvowels + %d): %c, *(vowels + %d): %c\n", i, vowels[i], i, *(pvowels + i), i, *(vowels + i));
}
```
@ -77,7 +77,7 @@ pvowels[3] = 'O';
for (i = 0; i < n; i++) {
printf("%c ", pvowels[i]);
}
printf("\\n");
printf("\n");
free(pvowels);
```
@ -113,7 +113,7 @@ for (i = 0; i < nrows; i++) {
for(j = 0; j < ncols; j++) {
printf("%c ", pvowels[i][j]);
}
printf("\\n");
printf("\n");
}
// Bebaskan baris-baris individu
@ -208,7 +208,7 @@ free(pnumbers)
for (j = 0; j <= i; j++) {
printf("%d", pnumbers[i][j]);
}
printf("\\n");
printf("\n");
}
for (i = 0; i < 3; i++) {
@ -250,7 +250,7 @@ free(pnumbers)
for (j = 0; j <= i; j++) {
printf("%d", pnumbers[i][j]);
}
printf("\\n");
printf("\n");
}
for (i = 0; i < 3; i++) {

4
content/binary_trees.md
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@ -93,7 +93,7 @@ int main() {
insert(test_list,4);
insert(test_list,3);
printDFS(test_list);
printf("\\n");
printf("\n");
}
void insert(node_t * tree, int val) {
@ -164,7 +164,7 @@ int main() {
insert(test_list,4);
insert(test_list,3);
printDFS(test_list);
printf("\\n");
printf("\n");
}
void insert(node_t * tree, int val) {

8
content/conditions.md
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@ -170,13 +170,13 @@ int num = 1;
switch (num) {
case 1:
printf("Nomor 1\\n");
printf("Nomor 1\n");
case 2:
printf("Nomor 2\\n");
printf("Nomor 2\n");
case 3:
printf("Nomor 3\\n");
printf("Nomor 3\n");
default:
printf("Nomor lain\\n");
printf("Nomor lain\n");
}
```

4
content/dynamic_allocation.md
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@ -110,7 +110,7 @@ mypoint coordinates: 10, 5
mypoint->x = 10;
mypoint->y =5 ;
printf("mypoint coordinates: %d, %d\\n", mypoint->x, mypoint->y);
printf("mypoint coordinates: %d, %d\n", mypoint->x, mypoint->y);
free(mypoint);
return 0;
}
@ -132,7 +132,7 @@ mypoint coordinates: 10, 5
mypoint->x = 10;
mypoint->y =5 ;
printf("mypoint coordinates: %d, %d\\n", mypoint->x, mypoint->y);
printf("mypoint coordinates: %d, %d\n", mypoint->x, mypoint->y);
free(mypoint);
return 0;
}

18
content/for_loops.md
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@ -61,7 +61,7 @@ int main() {
int n = sizeof(numbers) / sizeof(numbers[0]); // menghitung jumlah elemen
for (int i = 0; i < n; i++) {
printf("Elemen ke-%d: %d\\n", i, numbers[i]);
printf("Elemen ke-%d: %d\n", i, numbers[i]);
}
return 0;
@ -90,7 +90,7 @@ int main() {
for (int j = 1; j <= i; j++) {
printf("* ");
}
printf("\\n");
printf("\n");
}
return 0;
@ -144,15 +144,15 @@ int main() {
int n = sizeof(scores) / sizeof(scores[0]);
int total = 0;
printf("Daftar nilai siswa:\\n");
printf("Daftar nilai siswa:\n");
for (int i = 0; i < n; i++) {
printf("Siswa %d: %d\\n", i+1, scores[i]);
printf("Siswa %d: %d\n", i+1, scores[i]);
total += scores[i];
}
float average = (float)total / n;
printf("\\nTotal nilai: %d\\n", total);
printf("Rata-rata nilai: %.2f\\n", average);
printf("\nTotal nilai: %d\n", total);
printf("Rata-rata nilai: %.2f\n", average);
return 0;
}
@ -251,7 +251,7 @@ Tabel Perkalian 5x5:
#include <stdio.h>
int main() {
printf("Tabel Perkalian 5x5:\\n");
printf("Tabel Perkalian 5x5:\n");
// TODO: Gunakan nested for loops untuk mencetak tabel perkalian
// Baris dan kolom dari 1 hingga 5
@ -264,13 +264,13 @@ int main() {
#include <stdio.h>
int main() {
printf("Tabel Perkalian 5x5:\\n");
printf("Tabel Perkalian 5x5:\n");
for (int i = 1; i <= 5; i++) {
for (int j = 1; j <= 5; j++) {
printf("%-3d", i * j); // %-3d untuk format rata kiri dengan lebar 3 karakter
}
printf("\\n");
printf("\n");
}
return 0;

16
content/function_arguments_by_reference.md
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@ -23,9 +23,9 @@ void addone(int n) {
}
int n;
printf("Sebelum: %d\\n", n);
printf("Sebelum: %d\n", n);
addone(n);
printf("Setelah: %d\\n", n);
printf("Setelah: %d\n", n);
```
Namun, ini akan bekerja:
@ -37,9 +37,9 @@ void addone(int *n) {
}
int n;
printf("Sebelum: %d\\n", n);
printf("Sebelum: %d\n", n);
addone(&n);
printf("Setelah: %d\\n", n);
printf("Setelah: %d\n", n);
```
Perbedaannya adalah versi kedua dari `addone` menerima pointer ke variabel `n` sebagai argumen, dan kemudian bisa memanipulasinya, karena tahu di mana itu berada di memori. Perhatikan bahwa ketika memanggil fungsi `addone`, kita **harus** melewatkan referensi ke variabel `n`, dan bukan variabel itu sendiri - ini dilakukan agar fungsi tahu alamat dari variabel, dan tidak hanya menerima salinan dari variabel itu sendiri.
@ -122,9 +122,9 @@ Happy birthday! John is now 28 years old.
person john;
john.name = "John";
john.age = 27;
printf("%s is %d years old.\\n", john.name, john.age);
printf("%s is %d years old.\n", john.name, john.age);
birthday(&john);
printf("Happy birthday! %s is now %d years old.\\n", john.name, john.age);
printf("Happy birthday! %s is now %d years old.\n", john.name, john.age);
return 0;
}
---END_INITIAL_CODE---
@ -149,9 +149,9 @@ Happy birthday! John is now 28 years old.
person john;
john.name = "John";
john.age = 27;
printf("%s is %d years old.\\n", john.name, john.age);
printf("%s is %d years old.\n", john.name, john.age);
birthday(&john);
printf("Happy birthday! %s is now %d years old.\\n", john.name, john.age);
printf("Happy birthday! %s is now %d years old.\n", john.name, john.age);
return 0;
}
---END_SOLUTION_CODE---

22
content/function_pointers.md
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@ -41,17 +41,17 @@ Oke cukup teori. Mari kita coba dengan kode nyata. Lihat contoh ini:
#include <stdio.h>
void someFunction(int arg)
{
printf("This is someFunction being called and arg is: %d\\n", arg);
printf("Whoops leaving the function now!\\n");
printf("This is someFunction being called and arg is: %d\n", arg);
printf("Whoops leaving the function now!\n");
}
main()
{
void (*pf)(int);
pf = &someFunction;
printf("We're about to call someFunction() using a pointer!\\n");
printf("We're about to call someFunction() using a pointer!\n");
(pf)(5);
printf("Wow that was cool. Back to main now!\\n\\n");
printf("Wow that was cool. Back to main now!\n\n");
}
```
@ -74,7 +74,7 @@ main()
int c = 0;
while (c < sizeof(iarray)/sizeof(*iarray))
{
printf("%d \\t", iarray[c]);
printf("%d \t", iarray[c]);
c++;
}
}
@ -130,17 +130,17 @@ this is f3 and var is: 2
#include <stdio.h>
void f1(int var)
{
printf("this is f1 and var is: %d\\n", var);
printf("this is f1 and var is: %d\n", var);
}
void f2(int var)
{
printf("this is f2 and var is: %d\\n", var);
printf("this is f2 and var is: %d\n", var);
}
void f3(int var)
{
printf("this is f3 and var is: %d\\n", var);
printf("this is f3 and var is: %d\n", var);
}
int main()
@ -160,17 +160,17 @@ int main()
#include <stdio.h>
void f1(int var)
{
printf("this is f1 and var is: %d\\n", var);
printf("this is f1 and var is: %d\n", var);
}
void f2(int var)
{
printf("this is f2 and var is: %d\\n", var);
printf("this is f2 and var is: %d\n", var);
}
void f3(int var)
{
printf("this is f3 and var is: %d\\n", var);
printf("this is f3 and var is: %d\n", var);
}
int main()

2
content/functions.md
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@ -146,7 +146,7 @@ printf
void print_big(int number){
if(number > 10){
printf("%d is big\\n",number);
printf("%d is big\n",number);
}
}
---END_SOLUTION_CODE---

2
content/hello_world.md
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@ -160,7 +160,7 @@ int y = 10;
| Fungsi | Deskripsi | Contoh |
|--------|-----------|--------|
| printf() | Mencetak output ke layar | `printf("Halo Dunia\\n");` |
| printf() | Mencetak output ke layar | `printf("Halo Dunia\n");` |
| scanf() | Membaca input dari pengguna | `scanf("%d", &angka);` |
| getchar() | Membaca satu karakter | `char c = getchar();` |
| putchar() | Mencetak satu karakter | `putchar('A');` |

6
content/linked_lists.md
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@ -87,7 +87,7 @@ Mari kita buat fungsi yang mencetak semua item dari daftar. Untuk melakukan ini,
void print_list(node_t * head) {
node_t * current = head;
while (current != NULL) {
printf("%d\\n", current->val);
printf("%d\n", current->val);
current = current->next;
}
}
@ -289,7 +289,7 @@ pop(head)
void print_list(node_t * head) {
node_t * current = head;
while (current != NULL) {
printf("%d\\n", current->val);
printf("%d\n", current->val);
current = current->next;
}
}
@ -343,7 +343,7 @@ pop(head)
void print_list(node_t * head) {
node_t * current = head;
while (current != NULL) {
printf("%d\\n", current->val);
printf("%d\n", current->val);
current = current->next;
}
}

76
content/operators.md
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@ -46,17 +46,17 @@ Contoh:
int main() {
int a = 10, b = 3;
printf("a + b = %d\\n", a + b); // 13
printf("a - b = %d\\n", a - b); // 7
printf("a * b = %d\\n", a * b); // 30
printf("a / b = %d\\n", a / b); // 3 (pembagian integer)
printf("a %% b = %d\\n", a % b); // 1 (sisa bagi)
printf("a + b = %d\n", a + b); // 13
printf("a - b = %d\n", a - b); // 7
printf("a * b = %d\n", a * b); // 30
printf("a / b = %d\n", a / b); // 3 (pembagian integer)
printf("a %% b = %d\n", a % b); // 1 (sisa bagi)
a++; // a sekarang menjadi 11
printf("a++ = %d\\n", a); // 11
printf("a++ = %d\n", a); // 11
b--; // b sekarang menjadi 2
printf("b-- = %d\\n", b); // 2
printf("b-- = %d\n", b); // 2
return 0;
}
@ -81,16 +81,16 @@ Contoh:
int main() {
int x = 10;
printf("x awal: %d\\n", x); // 10
printf("x awal: %d\n", x); // 10
x += 5; // Sama dengan x = x + 5
printf("x += 5: %d\\n", x); // 15
printf("x += 5: %d\n", x); // 15
x -= 3; // Sama dengan x = x - 3
printf("x -= 3: %d\\n", x); // 12
printf("x -= 3: %d\n", x); // 12
x *= 2; // Sama dengan x = x * 2
printf("x *= 2: %d\\n", x); // 24
printf("x *= 2: %d\n", x); // 24
return 0;
}
@ -116,12 +116,12 @@ Contoh:
int main() {
int a = 5, b = 10;
printf("a == b: %d\\n", a == b); // 0 (salah)
printf("a != b: %d\\n", a != b); // 1 (benar)
printf("a > b: %d\\n", a > b); // 0 (salah)
printf("a < b: %d\\n", a < b); // 1 (benar)
printf("a >= b: %d\\n", a >= b); // 0 (salah)
printf("a <= b: %d\\n", a <= b); // 1 (benar)
printf("a == b: %d\n", a == b); // 0 (salah)
printf("a != b: %d\n", a != b); // 1 (benar)
printf("a > b: %d\n", a > b); // 0 (salah)
printf("a < b: %d\n", a < b); // 1 (benar)
printf("a >= b: %d\n", a >= b); // 0 (salah)
printf("a <= b: %d\n", a <= b); // 1 (benar)
return 0;
}
@ -146,17 +146,17 @@ int main() {
// AND: Benar jika kedua kondisi benar
if (x > 0 && y > 0) {
printf("Kedua angka positif\\n"); // Ditampilkan
printf("Kedua angka positif\n"); // Ditampilkan
}
// OR: Benar jika salah satu kondisi benar
if (x > 10 || y > 5) {
printf("Setidaknya satu angka lebih besar\\n"); // Ditampilkan
printf("Setidaknya satu angka lebih besar\n"); // Ditampilkan
}
// NOT: Membalikkan kondisi
if (!(x == y)) {
printf("x tidak sama dengan y\\n"); // Ditampilkan
printf("x tidak sama dengan y\n"); // Ditampilkan
}
return 0;
@ -184,10 +184,10 @@ int main() {
unsigned char a = 5; // 00000101
unsigned char b = 3; // 00000011
printf("a & b = %d\\n", a & b); // 1 (00000001)
printf("a | b = %d\\n", a | b); // 7 (00000111)
printf("a ^ b = %d\\n", a ^ b); // 6 (00000110)
printf("~a = %d\\n", ~a); // 250 (11111010 dalam 8-bit)
printf("a & b = %d\n", a & b); // 1 (00000001)
printf("a | b = %d\n", a | b); // 7 (00000111)
printf("a ^ b = %d\n", a ^ b); // 6 (00000110)
printf("~a = %d\n", ~a); // 250 (11111010 dalam 8-bit)
return 0;
}
@ -213,14 +213,14 @@ int max = (a > b) ? a : b; // Jika a > b maka max = a, jika tidak max = b
### Operator `sizeof`
```c
int num;
printf("Ukuran int: %zu byte\\n", sizeof(num)); // Ukuran dalam byte
printf("Ukuran int: %zu byte\n", sizeof(num)); // Ukuran dalam byte
```
### Operator Alamat (`&`) dan Pointer (`*`)
```c
int x = 5;
int *ptr = &x; // ptr menyimpan alamat dari x
printf("Nilai x: %d\\n", *ptr); // Mengakses nilai melalui pointer
printf("Nilai x: %d\n", *ptr); // Mengakses nilai melalui pointer
```
## Urutan Prioritas Operator
@ -255,11 +255,11 @@ int main() {
// Perkalian dilakukan dulu karena prioritas lebih tinggi
result = a + b * c; // Sama dengan a + (b * c) = 5 + 30 = 35
printf("a + b * c = %d\\n", result);
printf("a + b * c = %d\n", result);
// Gunakan kurung untuk mengganti urutan prioritas
result = (a + b) * c; // Sama dengan (a + b) * c = 15 * 3 = 45
printf("(a + b) * c = %d\\n", result);
printf("(a + b) * c = %d\n", result);
return 0;
}
@ -280,22 +280,22 @@ int main() {
// Menggunakan operator logika dan perbandingan
if (age >= 18 && has_license) {
printf("Anda bisa mengemudi\\n");
printf("Anda bisa mengemudi\n");
}
// Menggunakan operator aritmatika dan penugasan
score += bonus; // Menambahkan bonus ke skor
printf("Skor akhir: %d\\n", score);
printf("Skor akhir: %d\n", score);
// Menggunakan operator conditional
char *status = (score >= 75) ? "Lulus" : "Tidak Lulus";
printf("Status: %s\\n", status);
printf("Status: %s\n", status);
// Menggunakan operator modulo untuk mengecek genap/ganjil
if (score % 2 == 0) {
printf("Skor adalah bilangan genap\\n");
printf("Skor adalah bilangan genap\n");
} else {
printf("Skor adalah bilangan ganjil\\n");
printf("Skor adalah bilangan ganjil\n");
}
return 0;
@ -381,23 +381,23 @@ int main() {
// Penjumlahan
hasil = a + b;
printf("Hasil penjumlahan: %d\\n", hasil);
printf("Hasil penjumlahan: %d\n", hasil);
// Pengurangan
hasil = a - b;
printf("Hasil pengurangan: %d\\n", hasil);
printf("Hasil pengurangan: %d\n", hasil);
// Perkalian
hasil = a * b;
printf("Hasil perkalian: %d\\n", hasil);
printf("Hasil perkalian: %d\n", hasil);
// Pembagian
hasil = a / b;
printf("Hasil pembagian: %d\\n", hasil);
printf("Hasil pembagian: %d\n", hasil);
// Modulo
hasil = a % b;
printf("Sisa hasil bagi: %d\\n", hasil);
printf("Sisa hasil bagi: %d\n", hasil);
return 0;
}

32
content/pointer_arithmetics.md
View File

@ -29,12 +29,12 @@ int main() {
int intarray[5] = {10,20,30,40,50};
int i;
for(i = 0; i < 5; i++)
printf("intarray[%d] has value %d - and address @ %x\\n", i, intarray[i], &intarray[i]);
printf("intarray[%d] has value %d - and address @ %x\n", i, intarray[i], &intarray[i]);
int *intpointer = &intarray[3]; //point to the 4th element in the array
printf("address: %x - has value %d\\n", intpointer, *intpointer); //print the address of the 4th element
printf("address: %x - has value %d\n", intpointer, *intpointer); //print the address of the 4th element
intpointer++; //now increase the pointer's address so it points to the 5th elemnt in the array
printf("address: %x - has value %d\\n", intpointer, *intpointer); //print the address of the 5th element
printf("address: %x - has value %d\n", intpointer, *intpointer); //print the address of the 5th element
return 0;
}
```
@ -50,12 +50,12 @@ int main() {
int intarray[5] = {10,20,30,40,50};
int i;
for(i = 0; i < 5; i++)
printf("intarray[%d] has value %d - and address @ %x\\n", i, intarray[i], &intarray[i]);
printf("intarray[%d] has value %d - and address @ %x\n", i, intarray[i], &intarray[i]);
int *intpointer = &intarray[4]; //point to the 5th element in the array
printf("address: %x - has value %d\\n", intpointer, *intpointer); //print the address of the 5th element
printf("address: %x - has value %d\n", intpointer, *intpointer); //print the address of the 5th element
intpointer--; //now decrease the point's address so it points to the 4th element in the array
printf("address: %x - has value %d\\n", intpointer, *intpointer); //print the address of the 4th element
printf("address: %x - has value %d\n", intpointer, *intpointer); //print the address of the 4th element
return 0;
}
```
@ -71,12 +71,12 @@ int main() {
int intarray[5] = {10,20,30,40,50};
int i;
for(i = 0; i < 5; i++)
printf("intarray[%d] has value: %d - and address @ %x\\n", i, intarray[i], &intarray[i]);
printf("intarray[%d] has value: %d - and address @ %x\n", i, intarray[i], &intarray[i]);
int *intpointer = &intarray[1]; //point to the 2nd element in the array
printf("address: %x - has value %d\\n", intpointer, *intpointer); //print the address of the 2nd element
printf("address: %x - has value %d\n", intpointer, *intpointer); //print the address of the 2nd element
intpointer += 2; //now shift by two the point's address so it points to the 4th element in the array
printf("address: %x - has value %d\\n", intpointer, *intpointer); //print the addres of the 4th element
printf("address: %x - has value %d\n", intpointer, *intpointer); //print the addres of the 4th element
return 0;
}
```
@ -94,12 +94,12 @@ int main() {
int intarray[5] = {10,20,30,40,50};
int i;
for(i = 0; i < 5; i++)
printf("intarray[%d] has value: %d - and address @ %x\\n", i, intarray[i], &intarray[i]);
printf("intarray[%d] has value: %d - and address @ %x\n", i, intarray[i], &intarray[i]);
int *intpointer = &intarray[4]; //point to the 5th element in the array
printf("address: %x - has value %d\\n", intpointer, *intpointer); //print the address of the 5th element
printf("address: %x - has value %d\n", intpointer, *intpointer); //print the address of the 5th element
intpointer -= 2; //now shift by two the point's address so it points to the 3rd element in the array
printf("address: %x - has value %d\\n", intpointer, *intpointer); //print the address of the 3rd element
printf("address: %x - has value %d\n", intpointer, *intpointer); //print the address of the 3rd element
return 0;
}
```
@ -175,9 +175,9 @@ int main() {
// Test code
for (i = 0; i < 3; i++) {
if (parray[i] == &pointer[i]) {
printf("Matched!\\n");
printf("Matched!\n");
} else {
printf("Fail\\n");
printf("Fail\n");
}
}
return 0;
@ -200,9 +200,9 @@ int main() {
for (i = 0; i < 3; i++) {
if (parray[i] == &pointer[i]) {
printf("Matched!\\n");
printf("Matched!\n");
} else {
printf("Fail\\n");
printf("Fail\n");
}
}
return 0;

10
content/pointers.md
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@ -62,8 +62,8 @@ int a = 1;
/* definisikan variabel pointer, dan arahkan ke a menggunakan operator & */
int * pointer_to_a = &a;
printf("Nilai a adalah %d\\n", a);
printf("Nilai a juga %d\\n", *pointer_to_a);
printf("Nilai a adalah %d\n", a);
printf("Nilai a juga %d\n", *pointer_to_a);
```
Perhatikan bahwa kita menggunakan operator `&` untuk menunjuk ke variabel `a`, yang baru saja kita buat. Kita kemudian merujuk ke variabel tersebut menggunakan operator dereferencing.
@ -81,7 +81,7 @@ a += 1;
*pointer_to_a += 1;
/* akan mencetak 3 */
printf("Nilai dari a sekarang %d\\n", a);
printf("Nilai dari a sekarang %d\n", a);
```
---
@ -135,7 +135,7 @@ int main() {
/* pengujian kode */
if (pointer_to_n != &n) return 1;
if (*pointer_to_n != 11) return 1;
printf("Done!\\n");
printf("Done!\n");
return 0;
}
---END_INITIAL_CODE---
@ -151,7 +151,7 @@ int main() {
/* pengujian kode */
if (pointer_to_n != &n) return 1;
if (*pointer_to_n != 11) return 1;
printf("Done!\\n");
printf("Done!\n");
return 0;
}
---END_SOLUTION_CODE---

16
content/recursion.md
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@ -101,10 +101,10 @@ int factorial
int main()
{
/* kode pengujian */
printf("0! = %i\\n", factorial(0));
printf("1! = %i\\n", factorial(1));
printf("3! = %i\\n", factorial(3));
printf("5! = %i\\n", factorial(5));
printf("0! = %i\n", factorial(0));
printf("1! = %i\n", factorial(1));
printf("3! = %i\n", factorial(3));
printf("5! = %i\n", factorial(5));
}
/* definisikan fungsi Anda di sini (jangan lupa untuk deklarasikan) */
@ -118,10 +118,10 @@ int factorial
int main()
{
/* kode pengujian */
printf("0! = %i\\n", factorial(0));
printf("1! = %i\\n", factorial(1));
printf("3! = %i\\n", factorial(3));
printf("5! = %i\\n", factorial(5));
printf("0! = %i\n", factorial(0));
printf("1! = %i\n", factorial(1));
printf("3! = %i\n", factorial(3));
printf("5! = %i\n", factorial(5));
}
int factorial(int number)

22
content/strings.md
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@ -41,17 +41,17 @@ Kita bisa menggunakan perintah `printf` untuk memformat string bersama dengan st
char * name = "John Smith";
int age = 27;
/* mencetak 'John Smith is 27 years old.' */
printf("%s is %d years old.\\n", name, age);
printf("%s is %d years old.\n", name, age);
```
Perhatikan bahwa ketika mencetak string, kita harus menambahkan karakter baris baru (`\\n`) sehingga perintah `printf` berikutnya akan mencetak di baris baru.
Perhatikan bahwa ketika mencetak string, kita harus menambahkan karakter baris baru (`\n`) sehingga perintah `printf` berikutnya akan mencetak di baris baru.
## Panjang String
Fungsi 'strlen' mengembalikan panjang string yang harus dilewatkan sebagai argumen:
```c
char * name = "Nikhil";
printf("%d\\n",strlen(name));
printf("%d\n",strlen(name));
```
## Perbandingan String
@ -60,9 +60,9 @@ Fungsi `strncmp` membandingkan antara dua string, mengembalikan angka 0 jika mer
```c
char * name = "John";
if (strncmp(name, "John", 4) == 0) {
printf("Hello, John!\\n");
printf("Hello, John!\n");
} else {
printf("You are not John. Go away.\\n");
printf("You are not John. Go away.\n");
}
```
@ -73,9 +73,9 @@ Fungsi 'strncat' menambahkan n karakter pertama dari string src ke string tujuan
char dest[20]="Hello";
char src[20]="World";
strncat(dest,src,3);
printf("%s\\n",dest);
printf("%s\n",dest);
strncat(dest,src,20);
printf("%s\\n",dest);
printf("%s\n",dest);
```
---
@ -134,12 +134,12 @@ int main() {
last_name[0] = 'B';
sprintf(name, "%s %s", first_name, last_name);
if (strncmp(name, "John Boe", 100) == 0) {
printf("Done!\\n");
printf("Done!\n");
}
name[0]='\0';
strncat(name,first_name,4);
strncat(name,last_name,20);
printf("%s\\n",name);
printf("%s\n",name);
return 0;
}
---END_INITIAL_CODE---
@ -155,12 +155,12 @@ int main() {
last_name[0] = 'B';
sprintf(name, "%s %s", first_name, last_name);
if (strncmp(name, "John Boe", 100) == 0) {
printf("Done!\\n");
printf("Done!\n");
}
name[0]='\0';
strncat(name,first_name,4);
strncat(name,last_name,20);
printf("%s\\n",name);
printf("%s\n",name);
return 0;
}
---END_SOLUTION_CODE---

16
content/unions.md
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@ -26,12 +26,12 @@ Memungkinkan Anda untuk melihat setiap byte secara individual tanpa casting poin
```c
union intParts parts;
parts.theInt = 5968145; // angka acak > 255 (1 byte)
printf("The int is %i\\nThe bytes are [%i, %i, %i, %i]\\n", parts.theInt, parts.bytes[0], parts.bytes[1], parts.bytes[2], parts.bytes[3]);
printf("The int is %i\nThe bytes are [%i, %i, %i, %i]\n", parts.theInt, parts.bytes[0], parts.bytes[1], parts.bytes[2], parts.bytes[3]);
// vs
int theInt = parts.theInt;
printf("The int is %i\\nThe bytes are [%i, %i, %i, %i]\\n", theInt, *((char*)&theInt+0), *((char*)&theInt+1), *((char*)&theInt+2), *((char*)&theInt+3));
printf("The int is %i\nThe bytes are [%i, %i, %i, %i]\n", theInt, *((char*)&theInt+0), *((char*)&theInt+1), *((char*)&theInt+2), *((char*)&theInt+3));
// atau dengan sintaks array yang bisa sedikit lebih enak terkadang
printf("The int is %i\\nThe bytes are [%i, %i, %i, %i]\\n", theInt, ((char*)&theInt)[0], ((char*)&theInt)[1], ((char*)&theInt)[2], ((char*)&theInt)[3]);
printf("The int is %i\nThe bytes are [%i, %i, %i, %i]\n", theInt, ((char*)&theInt)[0], ((char*)&theInt)[1], ((char*)&theInt)[2], ((char*)&theInt)[3]);
```
Menggabungkan ini dengan struktur memungkinkan Anda membuat union "bertag" yang bisa digunakan untuk menyimpan beberapa tipe berbeda, satu per satu. Sebagai contoh, Anda mungkin memiliki struktur "number", tetapi Anda tidak ingin menggunakan sesuatu seperti ini:
@ -105,7 +105,7 @@ union Coins change;
for(int i = 0; i < sizeof(change) / sizeof(int); ++i) {
scanf("%i", change.coins + i); // kode BURUK! input selalu mencurigakan!
}
printf("There are %i quarters, %i dimes, %i nickels, and %i pennies\\n", change.quarter, change.dime, change.nickel, change.penny);
printf("There are %i quarters, %i dimes, %i nickels, and %i pennies\n", change.quarter, change.dime, change.nickel, change.penny);
```
---
@ -163,8 +163,8 @@ int main() {
// hanya pergi ke 18 karena 1 byte untuk terminasi 0 dan kita tidak mencetak yang terakhir dalam loop
for(int i = 0; i < 19; ++i)
printf("%c, ", intCharacters.chars[i]);
printf("%c]\\n", intCharacters.chars[19]);
printf("%s\\n", intCharacters.chars);
printf("%c]\n", intCharacters.chars[19]);
printf("%s\n", intCharacters.chars);
}
---END_INITIAL_CODE---
@ -181,7 +181,7 @@ int main() {
// hanya pergi ke 18 karena 1 byte untuk terminasi 0 dan kita tidak mencetak yang terakhir dalam loop
for(int i = 0; i < 19; ++i)
printf("%c, ", intCharacters.chars[i]);
printf("%c]\\n", intCharacters.chars[19]);
printf("%s\\n", intCharacters.chars);
printf("%c]\n", intCharacters.chars[19]);
printf("%s\n", intCharacters.chars);
}
---END_SOLUTION_CODE---

32
content/while_loops.md
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@ -53,7 +53,7 @@ Jika kondisi dalam perulangan while selalu benar, maka perulangan akan berjalan
```c
while (1) {
printf("Loop tak terbatas\\n");
printf("Loop tak terbatas\n");
// Perulangan ini akan berjalan selamanya
}
```
@ -121,12 +121,12 @@ int main() {
attempts++;
if (password == 1234) {
printf("Password benar! Akses diberikan.\\n");
printf("Password benar! Akses diberikan.\n");
break;
} else if (attempts < MAX_ATTEMPTS) {
printf("Password salah! Coba lagi (%d kesempatan tersisa): ", MAX_ATTEMPTS - attempts);
} else {
printf("Terlalu banyak percobaan salah. Akses ditolak.\\n");
printf("Terlalu banyak percobaan salah. Akses ditolak.\n");
}
}
@ -197,12 +197,12 @@ int i = 10;
// While loop - tidak akan mengeksekusi blok kode
while (i < 5) {
printf("Ini tidak akan dicetak\\n");
printf("Ini tidak akan dicetak\n");
}
// Do-while loop - akan mengeksekusi blok kode sekali
do {
printf("Ini akan dicetak sekali\\n");
printf("Ini akan dicetak sekali\n");
} while (i < 5);
```
@ -225,12 +225,12 @@ int main() {
attempts++;
if (password == 1234) {
printf("Password benar! Akses diberikan.\\n");
printf("Password benar! Akses diberikan.\n");
break;
} else if (attempts < MAX_ATTEMPTS) {
printf("Password salah! Coba lagi (%d kesempatan tersisa): ", MAX_ATTEMPTS - attempts);
} else {
printf("Terlalu banyak percobaan salah. Akses ditolak.\\n");
printf("Terlalu banyak percobaan salah. Akses ditolak.\n");
}
}
@ -249,25 +249,25 @@ int main() {
int choice;
do {
printf("\\nMenu:\\n");
printf("1. Tampilkan pesan\\n");
printf("2. Hitung angka\\n");
printf("3. Keluar\\n");
printf("\nMenu:\n");
printf("1. Tampilkan pesan\n");
printf("2. Hitung angka\n");
printf("3. Keluar\n");
printf("Pilih opsi (1-3): ");
scanf("%d", &choice);
switch (choice) {
case 1:
printf("Anda memilih untuk menampilkan pesan.\\n");
printf("Anda memilih untuk menampilkan pesan.\n");
break;
case 2:
printf("Anda memilih untuk menghitung angka.\\n");
printf("Anda memilih untuk menghitung angka.\n");
break;
case 3:
printf("Keluar dari program.\\n");
printf("Keluar dari program.\n");
break;
default:
printf("Opsi tidak valid. Silakan coba lagi.\\n");
printf("Opsi tidak valid. Silakan coba lagi.\n");
}
} while (choice != 3);
@ -343,7 +343,7 @@ int main() {
number++; // Tambahkan number setiap iterasi
}
printf("\\n");
printf("\n");
return 0;
}
---END_SOLUTION_CODE---

2
elemes

@ -1 +1 @@
Subproject commit 2505cd0977abbd7194ab44dfe7e75e362a9d889e
Subproject commit a124cf5e6d7ae07d7758a35172afa3e15dd20f9c